G.2) Calculating double integrals*

G.2.a)

Here's a region [Graphics:Images/index_gr_1.gif] plotted in the [Graphics:Images/index_gr_2.gif]-plane.

[Graphics:Images/index_gr_3.gif]

[Graphics:Images/index_gr_4.gif]

Go with
       [Graphics:Images/index_gr_5.gif]
and calculate
       [Graphics:Images/index_gr_6.gif]
by the method of least labor on your part.

G.2.b)

Here's another region [Graphics:Images/index_gr_7.gif] plotted in the [Graphics:Images/index_gr_8.gif]-plane.

[Graphics:Images/index_gr_9.gif]

[Graphics:Images/index_gr_10.gif]

Fancy dudes say that this is the cardiod described in polar coordinates
by the polar equation [Graphics:Images/index_gr_11.gif].

Go with
       [Graphics:Images/index_gr_12.gif]
and calculate
       [Graphics:Images/index_gr_13.gif]
by the method of least labor on your part.

Next, go with
       [Graphics:Images/index_gr_14.gif]
and calculate
       [Graphics:Images/index_gr_15.gif]
by the method of least labor on your part.

Compare the values of
       [Graphics:Images/index_gr_16.gif] and [Graphics:Images/index_gr_17.gif].
Discuss how you think that the shape and position of [Graphics:Images/index_gr_18.gif] account for the relationship between these two numbers.

G.2.c)

Here is another region [Graphics:Images/index_gr_19.gif] plotted in the [Graphics:Images/index_gr_20.gif]-plane.

[Graphics:Images/index_gr_21.gif]

[Graphics:Images/index_gr_22.gif]

Go with
       [Graphics:Images/index_gr_23.gif]
       [Graphics:Images/index_gr_24.gif] and
       [Graphics:Images/index_gr_25.gif]
and calculate
       [Graphics:Images/index_gr_26.gif],
       [Graphics:Images/index_gr_27.gif], and
       [Graphics:Images/index_gr_28.gif]
by the method of least labor on your part.
Look at the formulas for [Graphics:Images/index_gr_29.gif] and [Graphics:Images/index_gr_30.gif] and then look at the shape and position of [Graphics:Images/index_gr_31.gif] and explain why it was no surprise that
       [Graphics:Images/index_gr_32.gif] and [Graphics:Images/index_gr_33.gif]
came out the way they did.

G.2.d)

Here is another region [Graphics:Images/index_gr_34.gif] plotted in the [Graphics:Images/index_gr_35.gif]-plane.

[Graphics:Images/index_gr_36.gif]

[Graphics:Images/index_gr_37.gif]

Go with
       [Graphics:Images/index_gr_38.gif]
and calculate
       [Graphics:Images/index_gr_39.gif]
by the method of least labor on your part.

G.2.e)

Given that the region [Graphics:Images/index_gr_40.gif] consists of everything inside the ellipse
       [Graphics:Images/index_gr_41.gif],
go with
       [Graphics:Images/index_gr_42.gif]
and calculate
       [Graphics:Images/index_gr_43.gif]
by the method of least labor on your part.


Converted by Mathematica      November 23, 1999